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"You've rooted a notable hacker's system and you're sure that he has hidden
something juicy on there. Can you find his secret?"
Setup
-----
We are given a zip file, which contains a backup of the hacker's filesystem.
Solution
--------
A quick search shows nothing of interest outside of /home. However, inspecting
/home show a Pictures directory with several files named like "..._500.jpg",
perhaps something to pay attention to. In addition, Desktop/ contains a
clue.png file. If you spend much time studying these files you'll not turn up
any leads, as the real file of interest is the mysterious "hzpxbsklqvboyou" file
in the home directory.
There's no obvious way to make sense of this file. All of our real clues will
come from the hacker's .bash_history file. The history file is mostly junk, but
these few lines are significant:
wget https://gist.githubusercontent.com/Glitch-is/bc49ee73e5413f3081e5bcf5c1537e78/raw/c1f735f7eb36a20cb46b9841916d73017b5e46a3/eRkjLlksZp
mv eRkjLlksZp tool.py
./tool.py ../secret > ../hzpxbsklqvboyou
shred secret
rm tool.py
This explains where our "hzpxbsklqvboyou" file came from as well as what
happened to the original secret.
If you download the sourced Python script, you'll get this:
#!/usr/bin/python3
import sys
import base64
def encode(filename):
with open(filename, "r") as f:
s = f.readline().strip()
return base64.b64encode((''.join([chr(ord(s[x])+([5,-1,3,-3,2,15,-6,3,9,1,-3,-5,3,-15] * 3)[x]) for x in range(len(s))])).encode('utf-8')).decode('utf-8')[::-1]*5
if __name__ == "__main__":
print(encode(sys.argv[1]))
It takes a filename on the command-line, reads the first line of that file, and
applies several mutations to that text before printing it to stdout.
Now we know how secret was encoded. Reversing this code gives us the following
function, which we can run over "hzpxbsklqvboyou" to recover the original secret.
def decode(filename):
with open(filename, "r") as f:
s = f.readline().strip()
s = s[:int(len(s)/5)][::-1]
s = base64.b64decode(s)
lut = [5,-1,3,-3,2,15,-6,3,9,1,-3,-5,3,-15] * 3
s = (''.join( [chr( s[x] - lut[x]) for x in range(len(s))]))
return s
if __name__ == "__main__":
print(decode(sys.argv[1]))
IceCTF{good_ol_history_lesson}
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